Not really sure where to ask this question. And it may be a silly question but here goes; If the multiplier for one stop of aperture is 1.414 (the square root of 2) then what is the multiplier for a third of a stop?
Not really sure where to ask this question. And it may be a silly question but here goes; If the multiplier for one stop of aperture is 1.414 (the square root of 2) then what is the multiplier for a third of a stop?
1.1545561
Greg Lockrey
Wealth is a state of mind.
Money is just a tool.
Happiness is pedaling +25mph on a smooth road.
1.12246 or so.
You want a number that when multiplied by itself three times gives the correct multiple for a stop's worth of exposure change. Thus you take the cube root of 1.414, which is the sixth root of two.
ask me one on sport...
Greg Lockrey
Wealth is a state of mind.
Money is just a tool.
Happiness is pedaling +25mph on a smooth road.
It is my understanding the multiplier is the “square root of one plus the fraction”
If you want ½ stop increase, the multiplier is the square root of (1+ ½).
Exposure Increase
f/stop Time multiplier Aperture Increase
1/12 1.059 1.040833
1/6 1.122 1.080123
1/4 1.189 1.118034
1/3 1.260 1.154701
1/2 1.414 1.224745
1 2.000 1.414214
Of course it has been a loooong time since I studied math.
Bill Kumpf
Let's just round it to 1.15............
Bill Kumpf
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