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Thread: Loss of contrast with 4x10" pinhole camera

  1. #1

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    Loss of contrast with 4x10" pinhole camera

    Have been using a 4x10" PHOTONBOX Panoramic Pinhole camera Model D. Posted my experiences in the forum:
    http://www.largeformatphotography.in...ead.php?132753

    Twice developed negatives that seemingly had a high Base plus Fog and resulting contrast was low. Both times I experienced this, I was using outdated Bergger 200 film so attributed it to that. But then yesterday shot a scene using fresh HP5 and experienced again a seemingly high Base plus Fog and resulting low contrast. After sitting down and looking at the negatives, realized that all three negatives were taken with the sun directly hitting the pinhole. The pinhole aperture is in a very thin round disk of Stainless Steel so I figure that the sun's rays bouncing off the sides of the pinhole must be causing the "seemingly high B&F". Anyone have any ideas of how to blacken the sides of the pinhole?

    Tried using a black Sharpie to "darken" the the sides of pinholes in aluminum and stainless steel but size of the pinholes were majorly decreased in diameter and the black ink of the Sharpie dries with a gloss sheen that still reflects sunlight. Or should I just replace the pinhole with one made in aluminum or brass and research a way to chemically blackening the metal?

  2. #2
    Resident Heretic Bruce Watson's Avatar
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    Re: Loss of contrast with 4x10" pinhole camera

    Quote Originally Posted by Greg View Post
    But then yesterday shot a scene using fresh HP5 and experienced again a seemingly high Base plus Fog and resulting low contrast. After sitting down and looking at the negatives, realized that all three negatives were taken with the sun directly hitting the pinhole.
    ...
    Or should I just replace the pinhole with one made in aluminum or brass and research a way to chemically blackening the metal?
    Probably not the sides of the pinhole, but the fact that the inside of the box is being lit because of light coming through the pinhole at an angle. If that's true, all you need is a lens shade. And it's easy enough to test -- shade the pinhole once and see if the problem goes away. If it's a long exposure, tape a piece of cardboard in place to shade it.

    OTOH, if you really want to blacken the pinhole, for aluminum you can black anodize, for steel (and a collection of other surfaces) you can use black oxide coating. I don't know how much smaller these will make the diameter of the pinhole.

    Bruce Watson

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    Jim Jones's Avatar
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    Re: Loss of contrast with 4x10" pinhole camera

    It's natural for an ideally sized pinhole to have some reduced contrast due to light being scattered through diffraction. Darkening the pinhole either chemically or with a felt-tip pen will help reduce reflections. I've also slightly etched brass pinholes to reduce brightly reflective surfaces. Fortunately, very precise sun shades are easy to improvise, and are very compact.

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    Re: Loss of contrast with 4x10" pinhole camera

    Im not sure what the insides of these cameras are like but you may want to use black telescope flock instead of matt black paint to reduce light bouncing around.
    Cheers Shane

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    Jac@stafford.net's Avatar
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    Re: Loss of contrast with 4x10" pinhole camera

    Quote Originally Posted by SMBooth View Post
    Im not sure what the insides of these cameras are like but you may want to use black telescope flock instead of matt black paint to reduce light bouncing around.
    Right. Edmunds' black flocking paper is super effective.

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    Re: Loss of contrast with 4x10" pinhole camera

    Top and bottom of the inside of the camera is already covered with a material similar to black telescope flock. Anodizing the metal black seems to be the way to go. The process doesn't look to be all that difficult for me to do but for the maybe 2 small pieces of metal that I want to anodize black, will be contacting the local model RR organization. I donated to them a lot of HO scale pieces that I used as a kid. I know one or two of the members anodize small parts for their model RR layout so will be asking for a small favor.
    thanks,
    Greg

  7. #7
    Jac@stafford.net's Avatar
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    Re: Loss of contrast with 4x10" pinhole camera

    Anodizing black, or any color is inferior to a texture that does not reflect light. Anodizing is no cure whatsoever.
    .

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    Re: Loss of contrast with 4x10" pinhole camera

    Quote Originally Posted by Jac@stafford.net View Post
    Anodizing black, or any color is inferior to a texture that does not reflect light. Anodizing is no cure whatsoever.
    .
    Agree but the pinhole is only 0.013 inches in diameter and adding texture to the sides of the pinhole's aperture would present quite a challenge. Anodizing black no cure but only option to pursue.

  9. #9
    Ed Freniere
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    Re: Loss of contrast with 4x10" pinhole camera

    I think what you are seeing is diffracted stray light from from the pinhole, due to it being directly illuminated by the sun. There may be some small contribution caused by sunlight coming through the pinhole and illuminating a spot inside the camera, but I think it is a secondary effect. The best solution is to use a sunshade, or to aim the camera away from the sun.

    This question connects my professional life (optical engineer) to my avocation, so I couldn't resist proving this to myself and sharing it with all of you.

    A typical photographic scene has luminance Lscene of about 5 kcd/m^2 - see https://en.wikipedia.org/wiki/Orders...de_(luminance).

    The sun illuminates the pinhole with illuminance Esun of about 100 klux - see https://en.wikipedia.org/wiki/Lux.

    The intensity of light diffracted by the pinhole is (lambda/D) * 1/(pi^3 sin^3(theta) - see http://proceedings.spiedigitallibrar...ticleid=947646
    where lambda = wavelength of light, D = diameter of pinhole, theta = angle of the sun to a point on the image, pi = 3.14159.... The diffracted intensity has units of 1/sr (diffracted luminance/incident illuminance).

    The scene illuminance at the film = pi/(4F^2) * Lscene
    where F = f/number of the pinhole.

    The sun illuminance at the film = Esun * (diffracted intensity) * pi/(4F^2).

    The ratio of the two illuminance values (sun to scene) is = Esun * (diffracted intensity) / Lscene.

    The wavelength of visible light, mid-spectrum is 0.0005mm. Assuming D = 0.05mm and theta=30 degrees, we put this all together to find the ratio is about 1/19, or about 4 1/3 stops. That is, the diffracted stray light from the sun is about 4 1/3 stops down from the average scene brightness, which corresponds to a background fog.

  10. #10

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    Re: Loss of contrast with 4x10" pinhole camera

    Quote Originally Posted by photog_ed View Post
    I think what you are seeing is diffracted stray light from from the pinhole, due to it being directly illuminated by the sun. There may be some small contribution caused by sunlight coming through the pinhole and illuminating a spot inside the camera, but I think it is a secondary effect. The best solution is to use a sunshade, or to aim the camera away from the sun.

    This question connects my professional life (optical engineer) to my avocation, so I couldn't resist proving this to myself and sharing it with all of you.

    A typical photographic scene has luminance Lscene of about 5 kcd/m^2 - see https://en.wikipedia.org/wiki/Orders...de_(luminance).

    The sun illuminates the pinhole with illuminance Esun of about 100 klux - see https://en.wikipedia.org/wiki/Lux.

    The intensity of light diffracted by the pinhole is (lambda/D) * 1/(pi^3 sin^3(theta) - see http://proceedings.spiedigitallibrar...ticleid=947646
    where lambda = wavelength of light, D = diameter of pinhole, theta = angle of the sun to a point on the image, pi = 3.14159.... The diffracted intensity has units of 1/sr (diffracted luminance/incident illuminance).

    The scene illuminance at the film = pi/(4F^2) * Lscene
    where F = f/number of the pinhole.

    The sun illuminance at the film = Esun * (diffracted intensity) * pi/(4F^2).

    The ratio of the two illuminance values (sun to scene) is = Esun * (diffracted intensity) / Lscene.

    The wavelength of visible light, mid-spectrum is 0.0005mm. Assuming D = 0.05mm and theta=30 degrees, we put this all together to find the ratio is about 1/19, or about 4 1/3 stops. That is, the diffracted stray light from the sun is about 4 1/3 stops down from the average scene brightness, which corresponds to a background fog.
    Wow, my head is spinning... reminiscent of the time a Physics Professor (student of mine at the time) tried to explain to me (Photo Professor at the time) how he developed a method for focusing defocused images for NASA. Could you please translate your obviously well thought out post into a real simple laymen's termed explanation? Would greatly appreciate it.
    thanks

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