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http://www.largeformatphotography.in...s-4x5-F-Metric
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Hi Neil... There is a certain point on the lens Axis around which all rotations of the Axis should happen (it being constant with respect to tilts/swings). This point is the exact position of the lens entrance pupil, the purpose of a view camera is to shift/side shift/swing/tilt with respect to the entrance pupil, not the axis of the lens. Think of it as a sphere that the image area intersects, if the entrance pupil is not exactly at the centre of the sphere, the shape of the intersection is not circular, but elliptical... This is not me saying... it is physics.
In other words, you will still have the axis of the lens penetrating the sphere by its centre, but while the image area plane will be an intersection by the centre of the sphere, the image projected by the lens will have a different centre (on the same axis) where the entrance pupil will be repositioned... This will cause the intersection not to be of circular shape (as it would be if the entrance pupil was positioned exactly at the centre of the where) but elliptical.
Let me give you a practical example (which will make it - I think - easier to understand). Say that you are using a recessed board on your camera, now by doing this, you retain the lens axis constant, but you've moved the entrance pupil of the lens backwards... If you now tilt the lens, the entrance pupil will drop with respect to the image area's centre... The image area will then record the intersection plane of a (hypothetical) sphere, the centre of which is where the original lens entrance pupil position would be, if no recessed board would be used. But the lens will project towards the image area a cone which is part of a different sphere, which now has a new centre, that being the position of the entrance pupil of the actual lens used on the recessed board. Thus the image area will intercept a plane that is of elliptical shape.
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