I just got a new to me Wollensak Verito 8-3/4" f4.
It has no aperture markings...or rather it's got some marking made in whiteout. So I thought I'd use some math to figure out what they were. The first (biggest) needing to be f/4 by default.
So 8-3/4 inches is 222mm. When I measure the size of the aperture I get 45mm and 222/45 = 4.94...call that f/5.
What am i doing wrong?
Thanks for the help!
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