So oh smart one, where in the equation does the fact that on the equator at midnight looking vertically up at a declination 0 star, the star will be moving across the film or sensor at 1 deg of subject view every 4 minutes. 6 hours later, the star will be moving across the sensor at 0 velocity. And in between those two times the star will be moving at maximum speed to start off with and slowing down as you get to 6 hours from midnight. Declination hasn't changed so what parameter has changed and what spatial coordinates are important in calculating that change?
Sorry percepts,
I'm kind but not so much that I'd serve you as a teacher of the basic astronomy that you need to study. Just a detail - looking vertically up in the night (at the zenith) you don't look at a declination 0 star. This time your observing latitude plays roll... Happy studies!
If a star that's moving on the celestial sphere after 6 hrs stops to move it's the time to take pictures of it - no star trails, what bliss! Or maybe it's a time to take sleep, who knows what could happen in the next 6 hrs.
Don't care about that, it's not important. Cheers!
Well, I'll bite...
300mm/4 = 75mm
65mm/4 = 16.5mm
The 300 mm f/4 will gather much more light as it has a greater aperature than the 65mm f/4. As was said earlier, recording point sources like stars is dependant on the absolute aperature/diameter, and not the f/number of a lens. The 65mm lens will perform much worse at reacording star trails than the 300mm.
Kirk - www.keyesphoto.com
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