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OK, FWIW I think this is the quick-and-dirty way to convert a known change in azimuth to apparent angle of view, given a specific elevation.

For elevation Ev, and change in azimuth of Az, then:
...

Yes, that back-of-the-envelope calculation is correct. The skies were cloudier than we would have liked (we had to put plastic bags over the cameras when it rained!) but it was clear leading up to...

I see I mistyped -- I mean 45 degrees, not 45 minutes. The problem you alluded to -- multiple exposures on a single frame -- is just what I wanted to resolve. I have been using NOAA's online solar...

I think the relevant angles of view are determined by the focal length and film size. It's conventional to express the angle of view using the diagonal distance of the film, but that's of course the...

Thanks, Ted. I was interested in finding out how to account for the fact that we have the azimuth for all relevant points in the event, but the event takes place at 52-61 degrees above the horizon....

Won't be in Lincoln, which will have 1:25 of totality.

Yes, I ended up doing this empirically -- the sun traverses the 4x5 view in ~2:15. I should be able to capture nearly 2/3rds of the event on the 4x5, but all of it (with about 8 min. to spare) with...

Thanks, but I think I didn't make my question sufficiently clear. Yes, the sun "moves" 0.25 degrees/minute. Totality at my viewing location will be 2:30. The duration of start of eclipse to end of...

No, I'm not mad. I live 2 hours from the center of totality, so I thought that might be a convenient viewing spot.

No, the 12" goes on the 8x10. Yes, the sun's disc is roughly 0.5 degrees.

I plan to photograph the solar eclipse (weather-permitting) with both my 4x5 (210mm lens) and 8x10 (12" lens). From my viewing spot in Nebraska, the sun's azimuth will change nearly 80 degrees from...